![孙训方《材料力学》(第5版)(下册)配套题库【名校考研真题+课后习题+章节题库+模拟试题】](https://wfqqreader-1252317822.image.myqcloud.com/cover/762/27032762/b_27032762.jpg)
上QQ阅读APP看本书,新人免费读10天
设备和账号都新为新人
第14章 应变分析、电阻应变计法基础
1.图14-1所示为一直径为D的圆周,受扭矩Mn及轴向拉力P的作用,欲用电测法确定Mn及P之值,试问最少要贴几片电阻片且如何布置贴片位置?请写出扭矩Mn及轴向拉力P与测得应变值的关系式。材料的机械性能E、G、μ及圆轴几何尺寸均为已知。[武汉理工大学2010研]
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image051.jpg?sign=1739526202-iCiB97aCwZXdAYlrmh5SS1cZwXVxexS2-0-c4f0119499252b8fac2ddee46dcc4512)
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image052.jpg?sign=1739526202-Swtd5wxce7m6B1Du7w4rZllIF4If9wA4-0-ad965fe76586a2b91f6412f80e0b3c33)
图14-1 图14-2
解:如图14-2所示,分别测得时的应变
和
时的应变
即可。
(1)轴向拉力P:
(2)由任意角的应变公式:可知:
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image059.png?sign=1739526202-YyBhoAI4W58YVYUc3HEmS6aKfUxmtOT3-0-a4d59d44426c2a9d937e2774b48e2034)
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image060.png?sign=1739526202-p6Cfadvfj5zzADptSldnJEZR20imgu1G-0-b65f8088739563d50d62bbc9d6467d63)
可得:
又泊松比,可得:
则有:
由剪切胡克定律可得扭矩Mn:
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image066.png?sign=1739526202-QG1g1ZFy0cdOQWinLh4vh0HLu8WEuuTq-0-7be653eb4385c0b6e707342ff151dd2e)
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image067.png?sign=1739526202-D7APNcc0so4TH4mMUyVbCmD6rrX2ardE-0-7dfa062f3d5ba91f24090cc03568efa8)
2.如图14-3所示拉杆,F、b、h及材料的弹性常数E、μ均为已知,试求线段AB的正应变。[西北工业大学2004研]
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image068.jpg?sign=1739526202-XleL7uyIy4BsXnFjFXlP3kHT5zaRCHmG-0-9b343d6c63134fa0fc955d86281024bf)
图14-3 图14-4
解:(1)沿横截面取图14-4所示单元体,由已知得
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image069.jpg?sign=1739526202-w3GaVpBRjqeXlU32iC2h5X14KfFmztSS-0-969870edb8e2404f899b98d8b9d9cab3)
(2)斜截面=45°上的正应力为
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image071.jpg?sign=1739526202-bhk34iIuwpZyhAGLeJ6W0y45hAsTEWm9-0-f1e4c24a08a27fa6037d0593e1c42b10)
(3)将45°、
-45°代入广义胡克定律,则
=45°方向的正应变为
![](https://epubservercos.yuewen.com/9D81D2/15436380704495206/epubprivate/OEBPS/Images/image073.jpg?sign=1739526202-EclQma3fKmtk9YnvEeqNYXaZeuBOdSpA-0-8573443b2e26ccf2000d2462773f22c1)
即可得AB的正应变: